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Edit: _itertools.cpython-313.pyc
� 5:�i� � � � SS jr g )Nc � � [ U 5 n[ X15 n [ U5 nSR XE5 nU=( d [ U5 e! [ a U$ f = f)a� If *iterable* has only one item, return it. If it has zero items, return *default*. If it has more than one item, raise the exception given by *too_long*, which is ``ValueError`` by default. >>> only([], default='missing') 'missing' >>> only([1]) 1 >>> only([1, 2]) # doctest: +IGNORE_EXCEPTION_DETAIL Traceback (most recent call last): ... ValueError: Expected exactly one item in iterable, but got 1, 2, and perhaps more.' >>> only([1, 2], too_long=TypeError) # doctest: +IGNORE_EXCEPTION_DETAIL Traceback (most recent call last): ... TypeError Note that :func:`only` attempts to advance *iterable* twice to ensure there is only one item. See :func:`spy` or :func:`peekable` to check iterable contents less destructively. zLExpected exactly one item in iterable, but got {!r}, {!r}, and perhaps more.)�iter�next�format� ValueError� StopIteration)�iterable�default�too_long�it� first_value� second_value�msgs �E/opt/alt/python313/lib64/python3.13/importlib/resources/_itertools.py�onlyr sf � �, �h� �B��r�#�K� *��B�x� � � &��{� A� � �)�*�S�/�)�� � � � �� �s � A � A�A)NN)r � � r �<module>r s ��$r
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