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Edit: _utils.py
import os import re from pathlib import Path import pytest SIMPLE_VERSION_REGEX = re.compile(r'([0-9]+)\.([0-9]+)\.([0-9]+)') ILLEGAL_FILENAME_CHARS = r'\/:*?"<>|' def shorten_path(path: Path) -> Path: """ Returns the path relative to the current working directory if possible. Otherwise return the path unchanged. """ try: return path.relative_to(os.getcwd()) except ValueError: return path def get_valid_filename(s: str) -> str: """ Return the given string converted to a string that can be used for a clean filename. Taken from https://github.com/django/django/blob/master/django/utils/text.py """ s = str(s).strip().replace(' ', '_') s = re.sub(r'(?u)[^-\w.]', '', s) s = {'': 'empty', '.': 'dot', '..': 'dotdot'}.get(s, s) return s def might_be_valid_filename(s: str) -> bool: """ Returns false if the given string is definitely a path traversal or not a valid filename. Returns true if the string might be a valid filename. Note: This isn't secure, it just catches most accidental path traversals or invalid filenames. """ return not ( len(s) == 0 or s == '.' or s == '..' or any(c in s for c in ILLEGAL_FILENAME_CHARS) ) def simple_version_parse(version: str): """ Returns a 3 tuple of the versions major, minor, and patch. Raises a value error if the version string is unsupported. """ match = SIMPLE_VERSION_REGEX.match(version) if match is None: raise ValueError('Unsupported version format') return tuple(int(part) for part in match.groups()) def _pytest_expected_on_right() -> bool: """ Returns true if pytest prints string diffs correctly for: assert tested_value == expected_value Returns false if pytest prints string diffs correctly for: assert expected_value == tested_value """ # pytest diffs before version 5.4.0 assumed expected to be on the left hand side. try: pytest_version = simple_version_parse(pytest.__version__) except ValueError: return True else: return pytest_version >= (5, 4, 0) def flatten_dict(d: dict): """ Returns the flattened dict representation of the given dict. Example: >>> flatten_dict({ ... 'a': 1, ... 'b': { ... 'c': 2 ... }, ... 'd': {}, ... }) [(['a'], 1), (['b', 'c'], 2)] """ assert type(d) is dict result = [] _flatten_dict(d, result, []) return result def _flatten_dict(obj, result, prefix): if type(obj) is dict: for k, v in obj.items(): prefix.append(k) _flatten_dict(v, result, prefix) prefix.pop() else: result.append((list(prefix), obj)) def flatten_filesystem_dict(d): """ Returns the flattened dict of a nested dictionary structure describing a filesystem. Raises ``ValueError`` if any of the dictionary keys are invalid filenames. Example: >>> flatten_filesystem_dict({ ... 'file1.txt': '111', ... 'dir1': { ... 'file2.txt': '222' ... }, ... }) {'file1.txt': '111', 'dir1/file2.txt': '222'} """ result = {} for key_list, obj in flatten_dict(d): for i, key in enumerate(key_list): if not might_be_valid_filename(key): key_list_str = ''.join('[{!r}]'.format(k) for k in key_list[:i]) raise ValueError('Key {!r} in d{} must be a valid file name.'.format(key, key_list_str)) result['/'.join(key_list)] = obj return result
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